Data Analysis problem set
AdvancedIOAA 2018 | Beijing, China | Data Analysis D1 | 75 pt

2018 D1 | Dust and young stars: the IRX–β relation

As a by-product of star formation, interstellar dust absorbs ultraviolet (UV) and optical starlight and re-emits it in the far infrared (FIR, 10–300 μm).

1.1 The UV light of a galaxy comes mainly from young stars, so UV luminosity traces the star formation rate. Because dust strongly attenuates the UV, astronomers define the UV continuum slope β\beta:

fλ=Q⋅λβ,f_\lambda = Q\cdot\lambda^\beta,

where fλf_\lambda is the monochromatic flux (W m⁻³) and QQ a constant.

(D1.1.1) The AB magnitude is mAB=−2.5log⁡fν3631 Jym_{\rm AB} = -2.5\log\dfrac{f_\nu}{3631\ {\rm Jy}}. A typical galaxy has a roughly constant AB magnitude across the UV. What is its UV slope? (Hint: fνΔν=fλΔλf_\nu\Delta\nu = f_\lambda\Delta\lambda.) (6)

(D1.1.2) Table 1 gives infrared photometry of the z=6.60z = 6.60 galaxy CR7. Plot its AB magnitude against the logarithm of the rest-frame wavelength. (12)

(D1.1.3) Calculate CR7's UV slope, plot the best-fit UV continuum, and compare with (D1.1.1). Is CR7 dustier than the typical galaxy [YES/NO]? (Hint: write mABm_{\rm AB} in terms of λ\lambda and m1600m_{1600}, the AB magnitude at λ0=1600\lambda_0 = 1600 Å.) (5)

1.2 If dust absorbs UV photons and re-emits the energy as blackbody radiation, the UV slope relates to the ratio of FIR to UV flux:

IRX≡log⁡FFIRF1600=S(β),\mathrm{IRX} \equiv \log\frac{F_{\rm FIR}}{F_{1600}} = S(\beta),

where F1600F_{1600} is the observed flux at rest-frame 1600 Å, defined as Fλ=λfλF_\lambda = \lambda f_\lambda. Table 2 gives β\beta, F1600F_{1600} and FFIRF_{\rm FIR} for 20 nearby galaxies (Meurer et al. 1999).

(D1.2.1) Plot the IRX–β diagram and find a linear fit IRX=aβ+b\mathrm{IRX} = a\beta + b. (14)

(D1.2.2) Quantify the dispersion (in dex) between observed and predicted IRX:

σ=∑(ΔIRXi)2N−1,ΔIRXi=IRXi,obs−IRXi,pred.\sigma = \sqrt{\frac{\sum(\Delta{\rm IRX}_i)^2}{N-1}}, \qquad \Delta{\rm IRX}_i = {\rm IRX}_{i,\rm obs} - {\rm IRX}_{i,\rm pred}.

(6)

1.3 Under the same energy balance assumption,

FFIRF1600≈100.4A1600−1,\frac{F_{\rm FIR}}{F_{1600}} \approx 10^{0.4A_{1600}} - 1,

where AλA_\lambda is the dust absorption in magnitudes.

(D1.3.1) Express A1600A_{1600} as a function of IRX. (6)

(D1.3.2) Plot A1600A_{1600} against β\beta and find a linear fit A1600=a′β+b′A_{1600} = a'\beta + b'. (12)

(D1.3.3) If this model is correct, what is the UV slope β0\beta_0 of a dust-free galaxy? (2)

1.4 In 2016, ALMA observed CR7. The FIR continuum was not detected, with a 3σ3\sigma upper limit on the FIR flux of 1.5×10−191.5\times10^{-19} W m⁻².

(D1.4.1) Calculate the IRX of CR7. Is it an upper or a lower limit? (Hint: write F1600=λ0f1600F_{1600} = \lambda_0 f_{1600}, with f1600f_{1600} the observed flux at rest-frame 1600 Å.) (6)

(D1.4.2) Is the observation deep enough to show any deviation of CR7 from the local IRX–β relation [YES/NO]? Give the IRX difference. (6)

Table 1 | Observed-frame photometry of CR7 (z = 6.60)
BandYJHK
Central wavelength (μm)1.051.251.652.15
AB magnitude24.71 ± 0.1124.63 ± 0.1325.08 ± 0.1425.15 ± 0.15
Table 2 | UV slope, UV flux and FIR flux of 20 nearby galaxies
Galaxyβlog(F₁₆₀₀ / 10⁻³ W m⁻²)log(F_FIR / 10⁻³ W m⁻²)
NGC 4861−2.46−9.89−9.97
Mrk 153−2.41−10.37−10.92
Tol 1924-416−2.12−10.05−10.17
UGC 9560−2.02−10.38−10.41
NGC 3991−1.91−10.14−9.80
Mrk 357−1.80−10.58−10.37
Mrk 36−1.72−10.68−10.94
NGC 4670−1.65−10.02−9.85
NGC 3125−1.49−10.19−9.64
UGC 3838−1.41−10.81−10.55
NGC 7250−1.33−10.23−9.77
NGC 7714−1.23−10.16−9.32
NGC 3049−1.14−10.69−9.84
NGC 3310−1.05−9.84−8.83
NGC 2782−0.90−10.50−9.33
NGC 1614−0.76−10.91−8.84
NGC 6052−0.72−10.62−9.48
NGC 3504−0.56−10.41−8.96
NGC 4194−0.26−10.62−8.99
NGC 32560.16−10.32−8.44

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